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530420133 = 3176806711
BaseRepresentation
bin11111100111011…
…001000110100101
31100222002010122010
4133213121012211
52041241421013
6124344424433
716100332245
oct3747310645
91328063563
10530420133
11252454551
12129778119
1385b76389
1450633b25
15318767c3
hex1f9d91a5

530420133 has 4 divisors (see below), whose sum is σ = 707226848. Its totient is φ = 353613420.

The previous prime is 530420113. The next prime is 530420159. The reversal of 530420133 is 331024035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 530420133 - 25 = 530420101 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530420113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88403353 + ... + 88403358.

It is an arithmetic number, because the mean of its divisors is an integer number (176806712).

Almost surely, 2530420133 is an apocalyptic number.

It is an amenable number.

530420133 is a deficient number, since it is larger than the sum of its proper divisors (176806715).

530420133 is a wasteful number, since it uses less digits than its factorization.

530420133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 176806714.

The product of its (nonzero) digits is 1080, while the sum is 21.

The square root of 530420133 is about 23030.8517645353. The cubic root of 530420133 is about 809.4810133751.

Adding to 530420133 its reverse (331024035), we get a palindrome (861444168).

The spelling of 530420133 in words is "five hundred thirty million, four hundred twenty thousand, one hundred thirty-three".

Divisors: 1 3 176806711 530420133