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530423110411 = 691776683983
BaseRepresentation
bin1111011011111111010…
…11100101101100001011
31212201010002122211222121
413231333223211230023
532142301304013121
61043401212032111
753215244022265
oct7557753455413
91781102584877
10530423110411
11194a51021657
1286971762637
133b03208655c
141b95b92ab35
15dbe6988141
hex7b7fae5b0b

530423110411 has 4 divisors (see below), whose sum is σ = 530499801312. Its totient is φ = 530346419512.

The previous prime is 530423110397. The next prime is 530423110421. The reversal of 530423110411 is 114011324035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 530423110411 - 25 = 530423110379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530423110421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38335075 + ... + 38348908.

It is an arithmetic number, because the mean of its divisors is an integer number (132624950328).

Almost surely, 2530423110411 is an apocalyptic number.

530423110411 is a deficient number, since it is larger than the sum of its proper divisors (76690901).

530423110411 is an equidigital number, since it uses as much as digits as its factorization.

530423110411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76690900.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 530423110411 its reverse (114011324035), we get a palindrome (644434434446).

The spelling of 530423110411 in words is "five hundred thirty billion, four hundred twenty-three million, one hundred ten thousand, four hundred eleven".

Divisors: 1 6917 76683983 530423110411