Base | Representation |
---|---|
bin | 1111011100000000001… |
… | …11110011111000111111 |
3 | 1212201010121120201101212 |
4 | 13232000013303320333 |
5 | 32142310202233412 |
6 | 1043402034355035 |
7 | 53215363634336 |
oct | 7560007637077 |
9 | 1781117521355 |
10 | 530430508607 |
11 | 194a55214a6a |
12 | 8697412ba7b |
13 | 3b033776a9c |
14 | 1b95c8d4d1d |
15 | dbe744a222 |
hex | 7b801f3e3f |
530430508607 has 8 divisors (see below), whose sum is σ = 533021929920. Its totient is φ = 527842188160.
The previous prime is 530430508583. The next prime is 530430508609. The reversal of 530430508607 is 706805034035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530430508607 - 232 = 526135541311 is a prime.
It is a super-2 number, since 2×5304305086072 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530430508609) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 431894 + ... + 1116867.
It is an arithmetic number, because the mean of its divisors is an integer number (66627741240).
Almost surely, 2530430508607 is an apocalyptic number.
530430508607 is a deficient number, since it is larger than the sum of its proper divisors (2591421313).
530430508607 is a wasteful number, since it uses less digits than its factorization.
530430508607 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1550433.
The product of its (nonzero) digits is 302400, while the sum is 41.
The spelling of 530430508607 in words is "five hundred thirty billion, four hundred thirty million, five hundred eight thousand, six hundred seven".
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