Base | Representation |
---|---|
bin | 11000000111110000111001… |
… | …00011101100101001000111 |
3 | 20221210220002112111001000001 |
4 | 30003320130203230221013 |
5 | 23423030212224204133 |
6 | 304451433414502131 |
7 | 14113153022133142 |
oct | 1403703443545107 |
9 | 227726075431001 |
10 | 53043325225543 |
11 | 159a0603286a94 |
12 | 5b4819a364947 |
13 | 2379c6c1aa4c3 |
14 | d1544c573059 |
15 | 61eba2c7287d |
hex | 303e1c8eca47 |
53043325225543 has 4 divisors (see below), whose sum is σ = 53043341839600. Its totient is φ = 53043308611488.
The previous prime is 53043325225477. The next prime is 53043325225547. The reversal of 53043325225543 is 34552252334035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53043325225543 - 221 = 53043323128391 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53043325225493 and 53043325225502.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53043325225547) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1839618 + ... + 10462831.
It is an arithmetic number, because the mean of its divisors is an integer number (13260835459900).
Almost surely, 253043325225543 is an apocalyptic number.
53043325225543 is a deficient number, since it is larger than the sum of its proper divisors (16614057).
53043325225543 is a wasteful number, since it uses less digits than its factorization.
53043325225543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16614056.
The product of its (nonzero) digits is 6480000, while the sum is 46.
Adding to 53043325225543 its reverse (34552252334035), we get a palindrome (87595577559578).
The spelling of 53043325225543 in words is "fifty-three trillion, forty-three billion, three hundred twenty-five million, two hundred twenty-five thousand, five hundred forty-three".
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