5304424000333 has 4 divisors (see below), whose sum is σ = 5304457325980. Its totient is φ = 5304390674688.

The previous prime is 5304424000331. The next prime is 5304424000367. The reversal of 5304424000333 is 3330004244035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4087521584644 + 1216902415689 = 2021762^2 + 1103133^2 .

It is a cyclic number.

It is not a de Polignac number, because 5304424000333 - 2¹ = 5304424000331 is a prime.

It is a super-2 number, since 2×5304424000333² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5304424000295 and 5304424000304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5304424000331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16422918 + ... + 16742791.

It is an arithmetic number, because the mean of its divisors is an integer number (1326114331495).

Almost surely, 2^{5304424000333} is an apocalyptic number.

It is an amenable number.

5304424000333 is a deficient number, since it is larger than the sum of its proper divisors (33325647).

5304424000333 is a wasteful number, since it uses less digits than its factorization.

5304424000333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33325646.

The product of its (nonzero) digits is 51840, while the sum is 31.

Adding to 5304424000333 its reverse (3330004244035), we get a palindrome (8634428244368).

The spelling of 5304424000333 in words is "five trillion, three hundred four billion, four hundred twenty-four million, three hundred thirty-three", and thus it is an aban number.