Base | Representation |
---|---|
bin | 100110100110000110100… |
… | …0101000000000010010001 |
3 | 200210002212000011100020200 |
4 | 1031030031011000002101 |
5 | 1143402111012301413 |
6 | 15140504442325413 |
7 | 1055144361161430 |
oct | 115141505000221 |
9 | 20702760140220 |
10 | 5304504025233 |
11 | 176569a263666 |
12 | 71806b7b9869 |
13 | 2c629c07885a |
14 | 144a4cb61117 |
15 | 92eb0516573 |
hex | 4d30d140091 |
5304504025233 has 24 divisors (see below), whose sum is σ = 8862143279808. Its totient is φ = 2994625333152.
The previous prime is 5304504025207. The next prime is 5304504025279. The reversal of 5304504025233 is 3325204054035.
5304504025233 is a `hidden beast` number, since 53 + 0 + 45 + 0 + 40 + 2 + 523 + 3 = 666.
It is not a de Polignac number, because 5304504025233 - 228 = 5304235589777 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5304504025283) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 507214510 + ... + 507224967.
It is an arithmetic number, because the mean of its divisors is an integer number (369255969992).
Almost surely, 25304504025233 is an apocalyptic number.
It is an amenable number.
5304504025233 is a deficient number, since it is larger than the sum of its proper divisors (3557639254575).
5304504025233 is a wasteful number, since it uses less digits than its factorization.
5304504025233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1014439573 (or 1014439570 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 36.
Adding to 5304504025233 its reverse (3325204054035), we get a palindrome (8629708079268).
The spelling of 5304504025233 in words is "five trillion, three hundred four billion, five hundred four million, twenty-five thousand, two hundred thirty-three".
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