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5304504253541 = 172767112768219
BaseRepresentation
bin100110100110000110100…
…0101110111110001100101
3200210002212000120221102112
41031030031011313301211
51143402111042103131
615140504451250405
71055144363132153
oct115141505676145
920702760527375
105304504253541
11176569a3aa149
1271806b8a9a05
132c629c12874c
14144a4cbc03d3
1592eb055e02b
hex4d30d177c65

5304504253541 has 8 divisors (see below), whose sum is σ = 5618563793280. Its totient is φ = 4990670255808.

The previous prime is 5304504253519. The next prime is 5304504253549. The reversal of 5304504253541 is 1453524054035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5304504253541 is a prime.

It is a super-2 number, since 2×53045042535412 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5304504253549) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56337071 + ... + 56431148.

It is an arithmetic number, because the mean of its divisors is an integer number (702320474160).

Almost surely, 25304504253541 is an apocalyptic number.

It is an amenable number.

5304504253541 is a deficient number, since it is larger than the sum of its proper divisors (314059539739).

5304504253541 is a wasteful number, since it uses less digits than its factorization.

5304504253541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112771003.

The product of its (nonzero) digits is 720000, while the sum is 41.

The spelling of 5304504253541 in words is "five trillion, three hundred four billion, five hundred four million, two hundred fifty-three thousand, five hundred forty-one".

Divisors: 1 17 2767 47039 112768219 1917059723 312029661973 5304504253541