Base | Representation |
---|---|
bin | 100110100110010100101… |
… | …1001101101110110101101 |
3 | 200210011002010022121221202 |
4 | 1031030221121231312231 |
5 | 1143404044134432322 |
6 | 15141023535335245 |
7 | 1055162221224545 |
oct | 115145131556655 |
9 | 20704063277852 |
10 | 5304979217837 |
11 | 1765913516922 |
12 | 718182981525 |
13 | 2c6346656300 |
14 | 144a95cda325 |
15 | 92edc0ce292 |
hex | 4d32966ddad |
5304979217837 has 12 divisors (see below), whose sum is σ = 5744807554464. Its totient is φ = 4896594789840.
The previous prime is 5304979217773. The next prime is 5304979217921. The reversal of 5304979217837 is 7387129794035.
It is not a de Polignac number, because 5304979217837 - 26 = 5304979217773 is a prime.
It is a Smith number, since the sum of its digits (65) coincides with the sum of the digits of its prime factors.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5304979210837) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1716368 + ... + 3681830.
It is an arithmetic number, because the mean of its divisors is an integer number (478733962872).
Almost surely, 25304979217837 is an apocalyptic number.
It is an amenable number.
5304979217837 is a deficient number, since it is larger than the sum of its proper divisors (439828336627).
5304979217837 is a wasteful number, since it uses less digits than its factorization.
5304979217837 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1981460 (or 1981447 counting only the distinct ones).
The product of its (nonzero) digits is 80015040, while the sum is 65.
The spelling of 5304979217837 in words is "five trillion, three hundred four billion, nine hundred seventy-nine million, two hundred seventeen thousand, eight hundred thirty-seven".
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