Base | Representation |
---|---|
bin | 11000000111111101010111… |
… | …11010010000111011111011 |
3 | 20221211112101110202120110120 |
4 | 30003332223322100323323 |
5 | 23423132422431004210 |
6 | 304454502315344323 |
7 | 14113511036325564 |
oct | 1403765372207373 |
9 | 227745343676416 |
10 | 53050025250555 |
11 | 159a3431273a43 |
12 | 5b4954a1520a3 |
13 | 237a7992c3b48 |
14 | d158c632516b |
15 | 61ee46085270 |
hex | 303fabe90efb |
53050025250555 has 16 divisors (see below), whose sum is σ = 84897720174624. Its totient is φ = 28287453542400.
The previous prime is 53050025250553. The next prime is 53050025250581. The reversal of 53050025250555 is 55505252005035.
It is a happy number.
It is not a de Polignac number, because 53050025250555 - 21 = 53050025250553 is a prime.
It is a super-3 number, since 3×530500252505553 (a number of 42 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (53050025250553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 368254204 + ... + 368398233.
It is an arithmetic number, because the mean of its divisors is an integer number (5306107510914).
Almost surely, 253050025250555 is an apocalyptic number.
53050025250555 is a deficient number, since it is larger than the sum of its proper divisors (31847694924069).
53050025250555 is a wasteful number, since it uses less digits than its factorization.
53050025250555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 736657246.
The product of its (nonzero) digits is 937500, while the sum is 42.
The spelling of 53050025250555 in words is "fifty-three trillion, fifty billion, twenty-five million, two hundred fifty thousand, five hundred fifty-five".
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