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53050025250555 = 354801736652437
BaseRepresentation
bin11000000111111101010111…
…11010010000111011111011
320221211112101110202120110120
430003332223322100323323
523423132422431004210
6304454502315344323
714113511036325564
oct1403765372207373
9227745343676416
1053050025250555
11159a3431273a43
125b4954a1520a3
13237a7992c3b48
14d158c632516b
1561ee46085270
hex303fabe90efb

53050025250555 has 16 divisors (see below), whose sum is σ = 84897720174624. Its totient is φ = 28287453542400.

The previous prime is 53050025250553. The next prime is 53050025250581. The reversal of 53050025250555 is 55505252005035.

It is a happy number.

It is not a de Polignac number, because 53050025250555 - 21 = 53050025250553 is a prime.

It is a super-3 number, since 3×530500252505553 (a number of 42 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (53050025250553) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 368254204 + ... + 368398233.

It is an arithmetic number, because the mean of its divisors is an integer number (5306107510914).

Almost surely, 253050025250555 is an apocalyptic number.

53050025250555 is a deficient number, since it is larger than the sum of its proper divisors (31847694924069).

53050025250555 is a wasteful number, since it uses less digits than its factorization.

53050025250555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 736657246.

The product of its (nonzero) digits is 937500, while the sum is 42.

The spelling of 53050025250555 in words is "fifty-three trillion, fifty billion, twenty-five million, two hundred fifty thousand, five hundred fifty-five".

Divisors: 1 3 5 15 4801 14403 24005 72015 736652437 2209957311 3683262185 11049786555 3536668350037 10610005050111 17683341750185 53050025250555