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53050405011 = 317683468337
BaseRepresentation
bin110001011010000011…
…001111000010010011
312001221011200210122020
4301122003033002103
51332121400430021
640212050142523
73555432000552
oct613203170223
9161834623566
1053050405011
112055363052a
12a346581a43
135005a21ac6
1427d38d7d99
1515a75937c6
hexc5a0cf093

53050405011 has 4 divisors (see below), whose sum is σ = 70733873352. Its totient is φ = 35366936672.

The previous prime is 53050404991. The next prime is 53050405049. The reversal of 53050405011 is 11050405035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53050405011 - 26 = 53050404947 is a prime.

It is a super-2 number, since 2×530504050112 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (53050405711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8841734166 + ... + 8841734171.

It is an arithmetic number, because the mean of its divisors is an integer number (17683468338).

Almost surely, 253050405011 is an apocalyptic number.

53050405011 is a deficient number, since it is larger than the sum of its proper divisors (17683468341).

53050405011 is a wasteful number, since it uses less digits than its factorization.

53050405011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17683468340.

The product of its (nonzero) digits is 1500, while the sum is 24.

Adding to 53050405011 its sum of digits (24), we get a palindrome (53050405035).

The spelling of 53050405011 in words is "fifty-three billion, fifty million, four hundred five thousand, eleven".

Divisors: 1 3 17683468337 53050405011