Base | Representation |
---|---|
bin | 11000000111111110010110… |
… | …01100111111010111001011 |
3 | 20221211120202001122110102200 |
4 | 30003333023030333113023 |
5 | 23423140011331044003 |
6 | 304455030352131243 |
7 | 14113530042635142 |
oct | 1403771314772713 |
9 | 227746661573380 |
10 | 53050550253003 |
11 | 159a3680658066 |
12 | 5b49675b36b23 |
13 | 237a850cc1294 |
14 | d15935d48759 |
15 | 61ee771db6a3 |
hex | 303fcb33f5cb |
53050550253003 has 24 divisors (see below), whose sum is σ = 76669854442896. Its totient is φ = 35347983854400.
The previous prime is 53050550252993. The next prime is 53050550253011. The reversal of 53050550253003 is 30035205505035.
53050550253003 is a `hidden beast` number, since 5 + 3 + 0 + 50 + 550 + 2 + 53 + 0 + 0 + 3 = 666.
It is not a de Polignac number, because 53050550253003 - 218 = 53050549990859 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53050550253013) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 188090401 + ... + 188372237.
It is an arithmetic number, because the mean of its divisors is an integer number (3194577268454).
Almost surely, 253050550253003 is an apocalyptic number.
53050550253003 is a deficient number, since it is larger than the sum of its proper divisors (23619304189893).
53050550253003 is a wasteful number, since it uses less digits than its factorization.
53050550253003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 293035 (or 293032 counting only the distinct ones).
The product of its (nonzero) digits is 168750, while the sum is 36.
Adding to 53050550253003 its reverse (30035205505035), we get a palindrome (83085755758038).
The spelling of 53050550253003 in words is "fifty-three trillion, fifty billion, five hundred fifty million, two hundred fifty-three thousand, three".
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