Base | Representation |
---|---|
bin | 100110100110011000010… |
… | …0111011001010101100001 |
3 | 200210011101120001102002010 |
4 | 1031030300213121111201 |
5 | 1143404321130304241 |
6 | 15141043541343133 |
7 | 1055165221022463 |
oct | 115146047312541 |
9 | 20704346042063 |
10 | 5305100244321 |
11 | 1765975869909 |
12 | 7181b7407aa9 |
13 | 2c636574c507 |
14 | 144aa8002133 |
15 | 92ee7a38d16 |
hex | 4d3309d9561 |
5305100244321 has 8 divisors (see below), whose sum is σ = 7173093288384. Its totient is φ = 3486920348240.
The previous prime is 5305100244313. The next prime is 5305100244331. The reversal of 5305100244321 is 1234420015035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5305100244321 - 23 = 5305100244313 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5305100244331) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12453286746 + ... + 12453287171.
It is an arithmetic number, because the mean of its divisors is an integer number (896636661048).
Almost surely, 25305100244321 is an apocalyptic number.
It is an amenable number.
5305100244321 is a deficient number, since it is larger than the sum of its proper divisors (1867993044063).
5305100244321 is a wasteful number, since it uses less digits than its factorization.
5305100244321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24906573991.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 5305100244321 its reverse (1234420015035), we get a palindrome (6539520259356).
The spelling of 5305100244321 in words is "five trillion, three hundred five billion, one hundred million, two hundred forty-four thousand, three hundred twenty-one".
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