Base | Representation |
---|---|
bin | 1111011100001001110… |
… | …11101001001010001011 |
3 | 1212201100020102112001021 |
4 | 13232010323221022023 |
5 | 32142441332030003 |
6 | 1043414040133311 |
7 | 53220363560653 |
oct | 7560473511213 |
9 | 1781306375037 |
10 | 530511205003 |
11 | 194a968213aa |
12 | 86997167237 |
13 | 3b0473bc130 |
14 | 1b9694dd363 |
15 | dbee58a2bd |
hex | 7b84ee928b |
530511205003 has 16 divisors (see below), whose sum is σ = 585295595136. Its totient is φ = 477725045760.
The previous prime is 530511204959. The next prime is 530511205067. The reversal of 530511205003 is 300502115035.
It is a cyclic number.
It is not a de Polignac number, because 530511205003 - 213 = 530511196811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530511205603) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10524526 + ... + 10574812.
It is an arithmetic number, because the mean of its divisors is an integer number (36580974696).
Almost surely, 2530511205003 is an apocalyptic number.
530511205003 is a deficient number, since it is larger than the sum of its proper divisors (54784390133).
530511205003 is a wasteful number, since it uses less digits than its factorization.
530511205003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70134.
The product of its (nonzero) digits is 2250, while the sum is 25.
The spelling of 530511205003 in words is "five hundred thirty billion, five hundred eleven million, two hundred five thousand, three".
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