Base | Representation |
---|---|
bin | 110001011010001100… |
… | …001100111000101111 |
3 | 12001221100010012220111 |
4 | 301122030030320233 |
5 | 1332123001134003 |
6 | 40212212400451 |
7 | 3555460660366 |
oct | 613214147057 |
9 | 161840105814 |
10 | 53052755503 |
11 | 20554996490 |
12 | a347316127 |
13 | 5006365927 |
14 | 27d3d4a7dd |
15 | 15a78a9e6d |
hex | c5a30ce2f |
53052755503 has 8 divisors (see below), whose sum is σ = 57877920720. Its totient is φ = 48227954880.
The previous prime is 53052755467. The next prime is 53052755513. The reversal of 53052755503 is 30555725035.
53052755503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53052755503 - 213 = 53052747311 is a prime.
It is a super-2 number, since 2×530527555032 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53052755513) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 278203 + ... + 428371.
It is an arithmetic number, because the mean of its divisors is an integer number (7234740090).
Almost surely, 253052755503 is an apocalyptic number.
53052755503 is a deficient number, since it is larger than the sum of its proper divisors (4825165217).
53052755503 is a wasteful number, since it uses less digits than its factorization.
53052755503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 182297.
The product of its (nonzero) digits is 393750, while the sum is 40.
The spelling of 53052755503 in words is "fifty-three billion, fifty-two million, seven hundred fifty-five thousand, five hundred three".
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