Base | Representation |
---|---|
bin | 110001011010001101… |
… | …010101100001101011 |
3 | 12001221100200100001012 |
4 | 301122031111201223 |
5 | 1332123040144120 |
6 | 40212223014135 |
7 | 3555463340003 |
oct | 613215254153 |
9 | 161840610035 |
10 | 53053053035 |
11 | 20555079a84 |
12 | a34743a34b |
13 | 500643b198 |
14 | 27d3dc7003 |
15 | 15a79181c5 |
hex | c5a35586b |
53053053035 has 16 divisors (see below), whose sum is σ = 63844169760. Its totient is φ = 42322199040.
The previous prime is 53053052891. The next prime is 53053053073. The reversal of 53053053035 is 53035035035.
53053053035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53053053035 - 214 = 53053036651 is a prime.
It is a super-2 number, since 2×530530530352 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53053052992 and 53053053010.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6408659 + ... + 6416931.
It is an arithmetic number, because the mean of its divisors is an integer number (3990260610).
Almost surely, 253053053035 is an apocalyptic number.
53053053035 is a deficient number, since it is larger than the sum of its proper divisors (10791116725).
53053053035 is a wasteful number, since it uses less digits than its factorization.
53053053035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11758.
The product of its (nonzero) digits is 50625, while the sum is 32.
The spelling of 53053053035 in words is "fifty-three billion, fifty-three million, fifty-three thousand, thirty-five".
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