Base | Representation |
---|---|
bin | 11000001000000011011110… |
… | …11010110010010000010001 |
3 | 20221211211212001211000100102 |
4 | 30010001233122302100101 |
5 | 23423211132131122003 |
6 | 304500204011102145 |
7 | 14113655235503465 |
oct | 1404015732622021 |
9 | 227754761730312 |
10 | 53053305332753 |
11 | 159a4864844280 |
12 | 5b4a104741955 |
13 | 237ab9ca2129b |
14 | d15b17bd84a5 |
15 | 620089001588 |
hex | 30406f6b2411 |
53053305332753 has 16 divisors (see below), whose sum is σ = 58403017797696. Its totient is φ = 47791585712640.
The previous prime is 53053305332747. The next prime is 53053305332771. The reversal of 53053305332753 is 35723350335035.
It is not a de Polignac number, because 53053305332753 - 210 = 53053305331729 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 53053305332698 and 53053305332707.
It is not an unprimeable number, because it can be changed into a prime (53053305332953) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 293876 + ... + 10304997.
It is an arithmetic number, because the mean of its divisors is an integer number (3650188612356).
Almost surely, 253053305332753 is an apocalyptic number.
It is an amenable number.
53053305332753 is a deficient number, since it is larger than the sum of its proper divisors (5349712464943).
53053305332753 is a wasteful number, since it uses less digits than its factorization.
53053305332753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10603024.
The product of its (nonzero) digits is 6378750, while the sum is 47.
Adding to 53053305332753 its reverse (35723350335035), we get a palindrome (88776655667788).
The spelling of 53053305332753 in words is "fifty-three trillion, fifty-three billion, three hundred five million, three hundred thirty-two thousand, seven hundred fifty-three".
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