Base | Representation |
---|---|
bin | 111100010100001010111000… |
… | …1100011010000001111111011 |
3 | 2120120110220122022112021102011 |
4 | 1320220111301203100033323 |
5 | 1024014312243004233103 |
6 | 5120205401225550351 |
7 | 216515041532622415 |
oct | 17050256143201773 |
9 | 2516426568467364 |
10 | 530537740305403 |
11 | 144055879348366 |
12 | 4b6059279453b7 |
13 | 19a05656b0095c |
14 | 950224105b9b5 |
15 | 4150786732d6d |
hex | 1e285718d03fb |
530537740305403 has 32 divisors (see below), whose sum is σ = 549368531712000. Its totient is φ = 511816586803200.
The previous prime is 530537740305361. The next prime is 530537740305479. The reversal of 530537740305403 is 304503047735035.
It is a cyclic number.
It is not a de Polignac number, because 530537740305403 - 217 = 530537740174331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530537740305803) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 132535031800 + ... + 132535035802.
It is an arithmetic number, because the mean of its divisors is an integer number (17167766616000).
Almost surely, 2530537740305403 is an apocalyptic number.
530537740305403 is a deficient number, since it is larger than the sum of its proper divisors (18830791406597).
530537740305403 is a wasteful number, since it uses less digits than its factorization.
530537740305403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10723.
The product of its (nonzero) digits is 7938000, while the sum is 49.
The spelling of 530537740305403 in words is "five hundred thirty trillion, five hundred thirty-seven billion, seven hundred forty million, three hundred five thousand, four hundred three".
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