Base | Representation |
---|---|
bin | 11000001000000100111111… |
… | …01111110001110100001111 |
3 | 20221211220221120111102000112 |
4 | 30010002133233301310033 |
5 | 23423214312213023401 |
6 | 304500420253350235 |
7 | 14114014312331042 |
oct | 1404023757616417 |
9 | 227756846442015 |
10 | 53054116142351 |
11 | 159a5140498555 |
12 | 5b4a2b019837b |
13 | 237ac9b9ba38c |
14 | d15b93778c59 |
15 | 6200d52b13bb |
hex | 30409fbf1d0f |
53054116142351 has 16 divisors (see below), whose sum is σ = 56763717410400. Its totient is φ = 49436294025600.
The previous prime is 53054116142333. The next prime is 53054116142393. The reversal of 53054116142351 is 15324161145035.
It is a de Polignac number, because none of the positive numbers 2k-53054116142351 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53054116142299 and 53054116142308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53054116142851) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37483805 + ... + 38873433.
It is an arithmetic number, because the mean of its divisors is an integer number (3547732338150).
Almost surely, 253054116142351 is an apocalyptic number.
53054116142351 is a deficient number, since it is larger than the sum of its proper divisors (3709601268049).
53054116142351 is a wasteful number, since it uses less digits than its factorization.
53054116142351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1422650.
The product of its (nonzero) digits is 216000, while the sum is 41.
Adding to 53054116142351 its reverse (15324161145035), we get a palindrome (68378277287386).
The spelling of 53054116142351 in words is "fifty-three trillion, fifty-four billion, one hundred sixteen million, one hundred forty-two thousand, three hundred fifty-one".
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