Base | Representation |
---|---|
bin | 1111011100001110100… |
… | …00000001000001010011 |
3 | 1212201102221121121000121 |
4 | 13232013100001001103 |
5 | 32143031311200201 |
6 | 1043421545531111 |
7 | 53221345304416 |
oct | 7560720010123 |
9 | 1781387547017 |
10 | 530550100051 |
11 | 195006777874 |
12 | 869a81a3a97 |
13 | 3b052489a5a |
14 | 1b970745b7d |
15 | dc02bbe9a1 |
hex | 7b87401053 |
530550100051 has 4 divisors (see below), whose sum is σ = 530651529504. Its totient is φ = 530448670600.
The previous prime is 530550100039. The next prime is 530550100081. The reversal of 530550100051 is 150001055035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530550100051 - 211 = 530550098003 is a prime.
It is a super-2 number, since 2×5305501000512 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 530550099989 and 530550100025.
It is not an unprimeable number, because it can be changed into a prime (530550100001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50706880 + ... + 50717341.
It is an arithmetic number, because the mean of its divisors is an integer number (132662882376).
Almost surely, 2530550100051 is an apocalyptic number.
530550100051 is a deficient number, since it is larger than the sum of its proper divisors (101429453).
530550100051 is a wasteful number, since it uses less digits than its factorization.
530550100051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101429452.
The product of its (nonzero) digits is 1875, while the sum is 25.
Adding to 530550100051 its reverse (150001055035), we get a palindrome (680551155086).
The spelling of 530550100051 in words is "five hundred thirty billion, five hundred fifty million, one hundred thousand, fifty-one".
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