Base | Representation |
---|---|
bin | 111100010100010001101000… |
… | …0010001111101111000010001 |
3 | 2120120112022000001022002221102 |
4 | 1320220203100101331320101 |
5 | 1024020031413403323441 |
6 | 5120220153402234145 |
7 | 216516063316424045 |
oct | 17050432021757021 |
9 | 2516468001262842 |
10 | 530552214511121 |
11 | 144060a26695350 |
12 | 4b6086a71b5955 |
13 | 19a06b2273301a |
14 | 9502c154d4025 |
15 | 4150d322d669b |
hex | 1e288d047de11 |
530552214511121 has 8 divisors (see below), whose sum is σ = 578784686112864. Its totient is φ = 482319818259520.
The previous prime is 530552214511103. The next prime is 530552214511147. The reversal of 530552214511121 is 121115412255035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530552214511121 - 26 = 530552214511057 is a prime.
It is not an unprimeable number, because it can be changed into a prime (530552214511021) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3577640 + ... + 32770473.
It is an arithmetic number, because the mean of its divisors is an integer number (72348085764108).
Almost surely, 2530552214511121 is an apocalyptic number.
It is an amenable number.
530552214511121 is a deficient number, since it is larger than the sum of its proper divisors (48232471601743).
530552214511121 is a wasteful number, since it uses less digits than its factorization.
530552214511121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37675071.
The product of its (nonzero) digits is 60000, while the sum is 38.
Adding to 530552214511121 its reverse (121115412255035), we get a palindrome (651667626766156).
The spelling of 530552214511121 in words is "five hundred thirty trillion, five hundred fifty-two billion, two hundred fourteen million, five hundred eleven thousand, one hundred twenty-one".
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