Base | Representation |
---|---|
bin | 100110100110110100111… |
… | …0110011010001001110001 |
3 | 200210020212110220111100122 |
4 | 1031031221312122021301 |
5 | 1143413302440344022 |
6 | 15141323122500025 |
7 | 1055231060632643 |
oct | 115155166321161 |
9 | 20706773814318 |
10 | 5306060481137 |
11 | 17663188a3a59 |
12 | 718424b04615 |
13 | 2c6489676890 |
14 | 144b5975c893 |
15 | 93051eb3742 |
hex | 4d369d9a271 |
5306060481137 has 32 divisors (see below), whose sum is σ = 5986577286144. Its totient is φ = 4669657516800.
The previous prime is 5306060481131. The next prime is 5306060481143. The reversal of 5306060481137 is 7311840606035.
5306060481137 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (5306060481131) and next prime (5306060481143).
It is not a de Polignac number, because 5306060481137 - 24 = 5306060481121 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5306060481131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7464983 + ... + 8144819.
It is an arithmetic number, because the mean of its divisors is an integer number (187080540192).
Almost surely, 25306060481137 is an apocalyptic number.
It is an amenable number.
5306060481137 is a deficient number, since it is larger than the sum of its proper divisors (680516805007).
5306060481137 is a wasteful number, since it uses less digits than its factorization.
5306060481137 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 680169.
The product of its (nonzero) digits is 362880, while the sum is 44.
The spelling of 5306060481137 in words is "five trillion, three hundred six billion, sixty million, four hundred eighty-one thousand, one hundred thirty-seven".
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