Base | Representation |
---|---|
bin | 110001011010101101… |
… | …001011110011001111 |
3 | 12001221221101111101222 |
4 | 301122231023303033 |
5 | 1332132204324212 |
6 | 40213121553555 |
7 | 3555624321311 |
oct | 613255136317 |
9 | 161857344358 |
10 | 53061401807 |
11 | 20559861597 |
12 | a34a1a58bb |
13 | 50080a229b |
14 | 27d515b7b1 |
15 | 15a8516c72 |
hex | c5ab4bccf |
53061401807 has 4 divisors (see below), whose sum is σ = 53853363096. Its totient is φ = 52269440520.
The previous prime is 53061401791. The next prime is 53061401831. The reversal of 53061401807 is 70810416035.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 70810416035 = 5 ⋅14162083207.
It is a cyclic number.
It is not a de Polignac number, because 53061401807 - 24 = 53061401791 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53061403807) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 395980544 + ... + 395980677.
It is an arithmetic number, because the mean of its divisors is an integer number (13463340774).
Almost surely, 253061401807 is an apocalyptic number.
53061401807 is a deficient number, since it is larger than the sum of its proper divisors (791961289).
53061401807 is an equidigital number, since it uses as much as digits as its factorization.
53061401807 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 791961288.
The product of its (nonzero) digits is 20160, while the sum is 35.
The spelling of 53061401807 in words is "fifty-three billion, sixty-one million, four hundred one thousand, eight hundred seven".
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