Base | Representation |
---|---|
bin | 1001111000101110… |
… | …10011111111001010 |
3 | 111200220101200021222 |
4 | 10330113103333022 |
5 | 41332233231214 |
6 | 2234402402042 |
7 | 245346542234 |
oct | 47427237712 |
9 | 14626350258 |
10 | 5307711434 |
11 | 2284079183 |
12 | 1041660322 |
13 | 66782966c |
14 | 384cc1254 |
15 | 210e8a38e |
hex | 13c5d3fca |
5307711434 has 4 divisors (see below), whose sum is σ = 7961567154. Its totient is φ = 2653855716.
The previous prime is 5307711413. The next prime is 5307711439. The reversal of 5307711434 is 4341177035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 3332175625 + 1975535809 = 57725^2 + 44447^2 .
It is a super-2 number, since 2×53077114342 = 56343601333228672712, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5307711394 and 5307711403.
It is not an unprimeable number, because it can be changed into a prime (5307711439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1326927857 + ... + 1326927860.
Almost surely, 25307711434 is an apocalyptic number.
5307711434 is a deficient number, since it is larger than the sum of its proper divisors (2653855720).
5307711434 is a wasteful number, since it uses less digits than its factorization.
5307711434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2653855719.
The product of its (nonzero) digits is 35280, while the sum is 35.
The square root of 5307711434 is about 72854.0419880737. The cubic root of 5307711434 is about 1744.3585882478.
Adding to 5307711434 its reverse (4341177035), we get a palindrome (9648888469).
The spelling of 5307711434 in words is "five billion, three hundred seven million, seven hundred eleven thousand, four hundred thirty-four".
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