Base | Representation |
---|---|
bin | 110001011011110101… |
… | …000101011011011101 |
3 | 12002000020212002101001 |
4 | 301123311011123131 |
5 | 1332202021000302 |
6 | 40215033550301 |
7 | 3556243452451 |
oct | 613365053335 |
9 | 162006762331 |
10 | 53080250077 |
11 | 20569465578 |
12 | a354575391 |
13 | 500bc713ca |
14 | 27d7866661 |
15 | 15a9edb787 |
hex | c5bd456dd |
53080250077 has 4 divisors (see below), whose sum is σ = 53172244156. Its totient is φ = 52988256000.
The previous prime is 53080250053. The next prime is 53080250099. The reversal of 53080250077 is 77005208035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 51744420676 + 1335829401 = 227474^2 + 36549^2 .
It is a cyclic number.
It is not a de Polignac number, because 53080250077 - 211 = 53080248029 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53080250177) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45996174 + ... + 45997327.
It is an arithmetic number, because the mean of its divisors is an integer number (13293061039).
Almost surely, 253080250077 is an apocalyptic number.
It is an amenable number.
53080250077 is a deficient number, since it is larger than the sum of its proper divisors (91994079).
53080250077 is an equidigital number, since it uses as much as digits as its factorization.
53080250077 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91994078.
The product of its (nonzero) digits is 58800, while the sum is 37.
The spelling of 53080250077 in words is "fifty-three billion, eighty million, two hundred fifty thousand, seventy-seven".
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