Base | Representation |
---|---|
bin | 100110101000001000111… |
… | …1101011010000011100011 |
3 | 200210112011001000000021101 |
4 | 1031100101331122003203 |
5 | 1143440042001404120 |
6 | 15142511033535231 |
7 | 1055361005663404 |
oct | 115202175320343 |
9 | 20715131000241 |
10 | 5308880888035 |
11 | 176753594a44a |
12 | 718a91574517 |
13 | 2c6818a9a4ba |
14 | 144d461759ab |
15 | 931698ce90a |
hex | 4d411f5a0e3 |
5308880888035 has 4 divisors (see below), whose sum is σ = 6370657065648. Its totient is φ = 4247104710424.
The previous prime is 5308880888027. The next prime is 5308880888053.
5308880888035 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5308880888035 - 23 = 5308880888027 is a prime.
It is a super-2 number, since 2×53088808880352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 530888088799 + ... + 530888088808.
It is an arithmetic number, because the mean of its divisors is an integer number (1592664266412).
Almost surely, 25308880888035 is an apocalyptic number.
5308880888035 is a deficient number, since it is larger than the sum of its proper divisors (1061776177613).
5308880888035 is a wasteful number, since it uses less digits than its factorization.
5308880888035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1061776177612.
The product of its (nonzero) digits is 58982400, while the sum is 64.
The spelling of 5308880888035 in words is "five trillion, three hundred eight billion, eight hundred eighty million, eight hundred eighty-eight thousand, thirty-five".
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