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53090280853 = 61870332473
BaseRepresentation
bin110001011100011011…
…010110010110010101
312002000221201201000021
4301130123112112111
51332212102441403
640220032545141
73556424640631
oct613433262625
9162027651007
1053090280853
1120574096875
12a3579b21b1
135011073c8c
1427d8d17dc1
1515aad1d8bd
hexc5c6d6595

53090280853 has 4 divisors (see below), whose sum is σ = 53960613388. Its totient is φ = 52219948320.

The previous prime is 53090280823. The next prime is 53090280923. The reversal of 53090280853 is 35808209035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13432346404 + 39657934449 = 115898^2 + 199143^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53090280853 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53090280823) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435166176 + ... + 435166297.

It is an arithmetic number, because the mean of its divisors is an integer number (13490153347).

Almost surely, 253090280853 is an apocalyptic number.

It is an amenable number.

53090280853 is a deficient number, since it is larger than the sum of its proper divisors (870332535).

53090280853 is an equidigital number, since it uses as much as digits as its factorization.

53090280853 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 870332534.

The product of its (nonzero) digits is 259200, while the sum is 43.

Adding to 53090280853 its reverse (35808209035), we get a palindrome (88898489888).

The spelling of 53090280853 in words is "fifty-three billion, ninety million, two hundred eighty thousand, eight hundred fifty-three".

Divisors: 1 61 870332473 53090280853