Base | Representation |
---|---|
bin | 100110101000001110011… |
… | …0011100001101010101111 |
3 | 200210112121201101111020220 |
4 | 1031100130303201222233 |
5 | 1143440430042102101 |
6 | 15142541053542423 |
7 | 1055365345421430 |
oct | 115203463415257 |
9 | 20715551344226 |
10 | 5309062847151 |
11 | 176761962aa88 |
12 | 718b224a4a13 |
13 | 2c68476a900b |
14 | 144d623bd487 |
15 | 9317a873636 |
hex | 4d41cce1aaf |
5309062847151 has 16 divisors (see below), whose sum is σ = 8132356558848. Its totient is φ = 3017866687200.
The previous prime is 5309062847131. The next prime is 5309062847173. The reversal of 5309062847151 is 1517482609035.
It is not a de Polignac number, because 5309062847151 - 29 = 5309062846639 is a prime.
It is a super-2 number, since 2×53090628471512 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5309062847094 and 5309062847103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5309062847131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 661808860 + ... + 661816881.
It is an arithmetic number, because the mean of its divisors is an integer number (508272284928).
It is a 1-persistent number, because it is pandigital, but 2⋅5309062847151 = 10618125694302 is not.
Almost surely, 25309062847151 is an apocalyptic number.
5309062847151 is a deficient number, since it is larger than the sum of its proper divisors (2823293711697).
5309062847151 is a wasteful number, since it uses less digits than its factorization.
5309062847151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1323625942.
The product of its (nonzero) digits is 1814400, while the sum is 51.
The spelling of 5309062847151 in words is "five trillion, three hundred nine billion, sixty-two million, eight hundred forty-seven thousand, one hundred fifty-one".
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