Base | Representation |
---|---|
bin | 110001011100110101… |
… | …001110101001110001 |
3 | 12002001102111101012200 |
4 | 301130311032221301 |
5 | 1332220322040243 |
6 | 40220434213413 |
7 | 3556536414663 |
oct | 613465165161 |
9 | 162042441180 |
10 | 53097065073 |
11 | 205779aa968 |
12 | a35a124269 |
13 | 50125aac00 |
14 | 27d9ba2533 |
15 | 15ab70dad3 |
hex | c5cd4ea71 |
53097065073 has 54 divisors (see below), whose sum is σ = 87995912706. Its totient is φ = 30731590656.
The previous prime is 53097065069. The next prime is 53097065221. The reversal of 53097065073 is 37056079035.
53097065073 is a `hidden beast` number, since 53 + 0 + 97 + 0 + 6 + 507 + 3 = 666.
It can be written as a sum of positive squares in 9 ways, for example, as 3944844864 + 49152220209 = 62808^2 + 221703^2 .
It is not a de Polignac number, because 53097065073 - 22 = 53097065069 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53097065473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 53 ways as a sum of consecutive naturals, for example, 37052365 + ... + 37053797.
It is an arithmetic number, because the mean of its divisors is an integer number (1629553939).
Almost surely, 253097065073 is an apocalyptic number.
It is an amenable number.
53097065073 is a deficient number, since it is larger than the sum of its proper divisors (34898847633).
53097065073 is a wasteful number, since it uses less digits than its factorization.
53097065073 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2915 (or 1466 counting only the distinct ones).
The product of its (nonzero) digits is 595350, while the sum is 45.
The spelling of 53097065073 in words is "fifty-three billion, ninety-seven million, sixty-five thousand, seventy-three".
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