Base | Representation |
---|---|
bin | 1111011101000100100… |
… | …00000101101101111001 |
3 | 1212202121112000120210010 |
4 | 13232202100011231321 |
5 | 32144443243312441 |
6 | 1043534531212133 |
7 | 53235515625120 |
oct | 7564220055571 |
9 | 1782545016703 |
10 | 531003104121 |
11 | 1952194554a6 |
12 | 86ab3a47049 |
13 | 3b0c5298bb9 |
14 | 1b9b4986ab7 |
15 | dc2c853116 |
hex | 7ba2405b79 |
531003104121 has 64 divisors (see below), whose sum is σ = 888281579520. Its totient is φ = 275150407680.
The previous prime is 531003104119. The next prime is 531003104171. The reversal of 531003104121 is 121401300135.
It is not a de Polignac number, because 531003104121 - 21 = 531003104119 is a prime.
It is a super-2 number, since 2×5310031041212 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is not an unprimeable number, because it can be changed into a prime (531003104101) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2406525 + ... + 2617893.
It is an arithmetic number, because the mean of its divisors is an integer number (13879399680).
Almost surely, 2531003104121 is an apocalyptic number.
531003104121 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
It is an amenable number.
531003104121 is a deficient number, since it is larger than the sum of its proper divisors (357278475399).
531003104121 is a wasteful number, since it uses less digits than its factorization.
531003104121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211654.
The product of its (nonzero) digits is 360, while the sum is 21.
Adding to 531003104121 its reverse (121401300135), we get a palindrome (652404404256).
The spelling of 531003104121 in words is "five hundred thirty-one billion, three million, one hundred four thousand, one hundred twenty-one".
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