5310043150045 has 4 divisors (see below), whose sum is σ = 6372051780060. Its totient is φ = 4248034520032.

The previous prime is 5310043150033. The next prime is 5310043150051. The reversal of 5310043150045 is 5400513400135.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3902635809081 + 1407407340964 = 1975509^2 + 1186342^2 .

It is a cyclic number.

It is not a de Polignac number, because 5310043150045 - 2¹³ = 5310043141853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5310043149989 and 5310043150016.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 531004315000 + ... + 531004315009.

It is an arithmetic number, because the mean of its divisors is an integer number (1593012945015).

Almost surely, 2^{5310043150045} is an apocalyptic number.

It is an amenable number.

5310043150045 is a deficient number, since it is larger than the sum of its proper divisors (1062008630015).

5310043150045 is a wasteful number, since it uses less digits than its factorization.

5310043150045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1062008630014.

The product of its (nonzero) digits is 18000, while the sum is 31.

The spelling of 5310043150045 in words is "five trillion, three hundred ten billion, forty-three million, one hundred fifty thousand, forty-five".