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5310103 = 172910771
BaseRepresentation
bin10100010000011010010111
3100222210002111
4110100122113
52324410403
6305451451
763064231
oct24203227
910883074
105310103
112aa7617
121940b87
13113bc96
149c3251
156ed56d
hex510697

5310103 has 8 divisors (see below), whose sum is σ = 5816880. Its totient is φ = 4824960.

The previous prime is 5310061. The next prime is 5310119. The reversal of 5310103 is 3010135.

5310103 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5310103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5310133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4893 + ... + 5878.

It is an arithmetic number, because the mean of its divisors is an integer number (727110).

Almost surely, 25310103 is an apocalyptic number.

5310103 is a deficient number, since it is larger than the sum of its proper divisors (506777).

5310103 is a wasteful number, since it uses less digits than its factorization.

5310103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10817.

The product of its (nonzero) digits is 45, while the sum is 13.

The square root of 5310103 is about 2304.3660733486. The cubic root of 5310103 is about 174.4620541843.

Adding to 5310103 its reverse (3010135), we get a palindrome (8320238).

Subtracting from 5310103 its reverse (3010135), we obtain a cube (2299968 = 1323).

The spelling of 5310103 in words is "five million, three hundred ten thousand, one hundred three".

Divisors: 1 17 29 493 10771 183107 312359 5310103