Base | Representation |
---|---|
bin | 110001011101000100… |
… | …011100100010011111 |
3 | 12002001201000001010211 |
4 | 301131010130202133 |
5 | 1332222332212421 |
6 | 40221055513251 |
7 | 3556615340560 |
oct | 613504344237 |
9 | 162051001124 |
10 | 53101054111 |
11 | 2057a184996 |
12 | a35b528827 |
13 | 50133767a1 |
14 | 27da520167 |
15 | 15abc4a9e1 |
hex | c5d11c89f |
53101054111 has 16 divisors (see below), whose sum is σ = 61341876288. Its totient is φ = 45024768000.
The previous prime is 53101054103. The next prime is 53101054117. The reversal of 53101054111 is 11145010135.
53101054111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 53101054111 - 23 = 53101054103 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53101054117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 782601 + ... + 847741.
It is an arithmetic number, because the mean of its divisors is an integer number (3833867268).
Almost surely, 253101054111 is an apocalyptic number.
53101054111 is a deficient number, since it is larger than the sum of its proper divisors (8240822177).
53101054111 is a wasteful number, since it uses less digits than its factorization.
53101054111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66402.
The product of its (nonzero) digits is 300, while the sum is 22.
Adding to 53101054111 its reverse (11145010135), we get a palindrome (64246064246).
The spelling of 53101054111 in words is "fifty-three billion, one hundred one million, fifty-four thousand, one hundred eleven".
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