Base | Representation |
---|---|
bin | 110001011101000101… |
… | …111000101000111001 |
3 | 12002001201201012121202 |
4 | 301131011320220321 |
5 | 1332222431300403 |
6 | 40221111543545 |
7 | 3556621501445 |
oct | 613505705071 |
9 | 162051635552 |
10 | 53101431353 |
11 | 2057a412363 |
12 | a35b68abb5 |
13 | 50134793c9 |
14 | 27da5bb825 |
15 | 15abcc2688 |
hex | c5d178a39 |
53101431353 has 6 divisors (see below), whose sum is σ = 56408787246. Its totient is φ = 49977817472.
The previous prime is 53101431349. The next prime is 53101431367. The reversal of 53101431353 is 35313410135.
53101431353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 3 ways, for example, as 12735799609 + 40365631744 = 112853^2 + 200912^2 .
It is not a de Polignac number, because 53101431353 - 22 = 53101431349 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53101431373) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 91870700 + ... + 91871277.
It is an arithmetic number, because the mean of its divisors is an integer number (9401464541).
Almost surely, 253101431353 is an apocalyptic number.
It is an amenable number.
53101431353 is a deficient number, since it is larger than the sum of its proper divisors (3307355893).
53101431353 is a wasteful number, since it uses less digits than its factorization.
53101431353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183742011 (or 183741994 counting only the distinct ones).
The product of its (nonzero) digits is 8100, while the sum is 29.
Adding to 53101431353 its reverse (35313410135), we get a palindrome (88414841488).
The spelling of 53101431353 in words is "fifty-three billion, one hundred one million, four hundred thirty-one thousand, three hundred fifty-three".
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