Base | Representation |
---|---|
bin | 110001011101000101… |
… | …111000101001000111 |
3 | 12002001201201012122021 |
4 | 301131011320221013 |
5 | 1332222431300432 |
6 | 40221111544011 |
7 | 3556621501465 |
oct | 613505705107 |
9 | 162051635567 |
10 | 53101431367 |
11 | 2057a412376 |
12 | a35b68b007 |
13 | 501347940a |
14 | 27da5bb835 |
15 | 15abcc2697 |
hex | c5d178a47 |
53101431367 has 2 divisors, whose sum is σ = 53101431368. Its totient is φ = 53101431366.
The previous prime is 53101431349. The next prime is 53101431373. The reversal of 53101431367 is 76313410135.
53101431367 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53101431367 - 211 = 53101429319 is a prime.
It is a super-2 number, since 2×531014313672 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53101431767) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26550715683 + 26550715684.
It is an arithmetic number, because the mean of its divisors is an integer number (26550715684).
Almost surely, 253101431367 is an apocalyptic number.
53101431367 is a deficient number, since it is larger than the sum of its proper divisors (1).
53101431367 is an equidigital number, since it uses as much as digits as its factorization.
53101431367 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22680, while the sum is 34.
The spelling of 53101431367 in words is "fifty-three billion, one hundred one million, four hundred thirty-one thousand, three hundred sixty-seven".
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