Search a number
-
+
53102221200000 = 27325572461653
BaseRepresentation
bin11000001001011110100110…
…00010000000101010000000
320222000112010002122112102100
430010233103002000222000
523430011322111400000
6304534453523550400
714120336354510400
oct1404572302005200
9228015102575370
1053102221200000
1115a1358654a345
125b5769652b400
132382696ca762b
14d1823855a800
1562149d5e6a00
hex304bd3080a80

53102221200000 has 1728 divisors, whose sum is σ = 223002818078040. Its totient is φ = 12092774400000.

The previous prime is 53102221199981. The next prime is 53102221200019. The reversal of 53102221200000 is 212220135.

It is an interprime number because it is at equal distance from previous prime (53102221199981) and next prime (53102221200019).

It can be written as a sum of positive squares in 12 ways, for example, as 36637259448384 + 16464961751616 = 6052872^2 + 4057704^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 81320399674 + ... + 81320400326.

Almost surely, 253102221200000 is an apocalyptic number.

53102221200000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53102221200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (111501409039020).

53102221200000 is an abundant number, since it is smaller than the sum of its proper divisors (169900596878040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53102221200000 is an equidigital number, since it uses as much as digits as its factorization.

53102221200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1173 (or 1131 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 18.

Adding to 53102221200000 its reverse (212220135), we get a palindrome (53102433420135).

The spelling of 53102221200000 in words is "fifty-three trillion, one hundred two billion, two hundred twenty-one million, two hundred thousand".