Base | Representation |
---|---|
bin | 111100010111101101010101… |
… | …1010110011101000110001100 |
3 | 2120122012101212110201002111022 |
4 | 1320233122223112131012030 |
5 | 1024100244214040130012 |
6 | 5121221024332413312 |
7 | 216565135530303314 |
oct | 17057325326350614 |
9 | 2518171773632438 |
10 | 531024041333132 |
11 | 144223038623176 |
12 | 4b684025017238 |
13 | 19a3c476b0a379 |
14 | 951b9b4b68444 |
15 | 415d249896472 |
hex | 1e2f6ab59d18c |
531024041333132 has 12 divisors (see below), whose sum is σ = 943162103263800. Its totient is φ = 261549154686336.
The previous prime is 531024041333119. The next prime is 531024041333147. The reversal of 531024041333132 is 231333140420135.
It is a junction number, because it is equal to n+sod(n) for n = 531024041333092 and 531024041333101.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 990716494757 + ... + 990716495292.
It is an arithmetic number, because the mean of its divisors is an integer number (78596841938650).
Almost surely, 2531024041333132 is an apocalyptic number.
It is an amenable number.
531024041333132 is a deficient number, since it is larger than the sum of its proper divisors (412138061930668).
531024041333132 is a wasteful number, since it uses less digits than its factorization.
531024041333132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1981432990120 (or 1981432990118 counting only the distinct ones).
The product of its (nonzero) digits is 77760, while the sum is 35.
Adding to 531024041333132 its reverse (231333140420135), we get a palindrome (762357181753267).
The spelling of 531024041333132 in words is "five hundred thirty-one trillion, twenty-four billion, forty-one million, three hundred thirty-three thousand, one hundred thirty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •