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53104104043 = 91515803093
BaseRepresentation
bin110001011101010000…
…000101001001101011
312002001220201222212021
4301131100011021223
51332224122312133
640221245125311
73556653302524
oct613520051153
9162056658767
1053104104043
11205809783a1
12a360559837
135013ba3a93
1427daab584b
1515ac14e52d
hexc5d40526b

53104104043 has 4 divisors (see below), whose sum is σ = 53109916288. Its totient is φ = 53098291800.

The previous prime is 53104104019. The next prime is 53104104077. The reversal of 53104104043 is 34040140135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53104104043 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53104103999 and 53104104017.

It is not an unprimeable number, because it can be changed into a prime (53104104083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2892396 + ... + 2910697.

It is an arithmetic number, because the mean of its divisors is an integer number (13277479072).

Almost surely, 253104104043 is an apocalyptic number.

53104104043 is a deficient number, since it is larger than the sum of its proper divisors (5812245).

53104104043 is an equidigital number, since it uses as much as digits as its factorization.

53104104043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5812244.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 53104104043 its reverse (34040140135), we get a palindrome (87144244178).

The spelling of 53104104043 in words is "fifty-three billion, one hundred four million, one hundred four thousand, forty-three".

Divisors: 1 9151 5803093 53104104043