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5310411005113 = 431109423112601
BaseRepresentation
bin100110101000110110100…
…1010010101110010111001
3200210200002200012000022021
41031101231022111302321
51144001210204130423
615143322533354441
71055443635525214
oct115215512256271
920720080160267
105310411005113
111768150630015
12719239a98a21
132c6a00aa5b16
1414504d47877b
1593208dc795d
hex4d46d295cb9

5310411005113 has 8 divisors (see below), whose sum is σ = 5322828059136. Its totient is φ = 5297994396000.

The previous prime is 5310411005041. The next prime is 5310411005171. The reversal of 5310411005113 is 3115001140135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5310411005113 - 233 = 5301821070521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5310411000113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47105013 + ... + 47217613.

It is an arithmetic number, because the mean of its divisors is an integer number (665353507392).

Almost surely, 25310411005113 is an apocalyptic number.

It is an amenable number.

5310411005113 is a deficient number, since it is larger than the sum of its proper divisors (12417054023).

5310411005113 is a wasteful number, since it uses less digits than its factorization.

5310411005113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 222455.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 5310411005113 its reverse (3115001140135), we get a palindrome (8425412145248).

The spelling of 5310411005113 in words is "five trillion, three hundred ten billion, four hundred eleven million, five thousand, one hundred thirteen".

Divisors: 1 431 109423 112601 47161313 48531031 12321139223 5310411005113