53104345231253 has 4 divisors (see below), whose sum is σ = 55899310769760. Its totient is φ = 50309379692748.

The previous prime is 53104345231241. The next prime is 53104345231313. The reversal of 53104345231253 is 35213254340135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 53104345231253 - 2¹⁰ = 53104345230229 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53104345231253.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53104345231753) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1397482769225 + ... + 1397482769262.

It is an arithmetic number, because the mean of its divisors is an integer number (13974827692440).

Almost surely, 2^{53104345231253} is an apocalyptic number.

It is an amenable number.

53104345231253 is a deficient number, since it is larger than the sum of its proper divisors (2794965538507).

53104345231253 is a wasteful number, since it uses less digits than its factorization.

53104345231253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2794965538506.

The product of its (nonzero) digits is 648000, while the sum is 41.

Adding to 53104345231253 its reverse (35213254340135), we get a palindrome (88317599571388).

The spelling of 53104345231253 in words is "fifty-three trillion, one hundred four billion, three hundred forty-five million, two hundred thirty-one thousand, two hundred fifty-three".