Base | Representation |
---|---|
bin | 100110101001001000100… |
… | …0111011001100101111101 |
3 | 200210201122201020012100122 |
4 | 1031102101013121211331 |
5 | 1144003424114322023 |
6 | 15143502442304325 |
7 | 1055464611650564 |
oct | 115222107314575 |
9 | 20721581205318 |
10 | 5311014214013 |
11 | 176843007a872 |
12 | 719387ab80a5 |
13 | 2c6a98a56171 |
14 | 1450a9618bdb |
15 | 93241d2b2c8 |
hex | 4d4911d997d |
5311014214013 has 8 divisors (see below), whose sum is σ = 5354130409536. Its totient is φ = 5268002544000.
The previous prime is 5311014214003. The next prime is 5311014214019. The reversal of 5311014214013 is 3104124101135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5311014214013 - 210 = 5311014212989 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5311014214019) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26029343 + ... + 26232588.
It is an arithmetic number, because the mean of its divisors is an integer number (669266301192).
Almost surely, 25311014214013 is an apocalyptic number.
It is an amenable number.
5311014214013 is a deficient number, since it is larger than the sum of its proper divisors (43116195523).
5311014214013 is a wasteful number, since it uses less digits than its factorization.
5311014214013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52262755.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 5311014214013 its reverse (3104124101135), we get a palindrome (8415138315148).
The spelling of 5311014214013 in words is "five trillion, three hundred eleven billion, fourteen million, two hundred fourteen thousand, thirteen".
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