Base | Representation |
---|---|
bin | 100110101001001000100… |
… | …1000100000011110001111 |
3 | 200210201122201202221121022 |
4 | 1031102101020200132033 |
5 | 1144003424203114320 |
6 | 15143502452424355 |
7 | 1055464614300161 |
oct | 115222110403617 |
9 | 20721581687538 |
10 | 5311014504335 |
11 | 1768430258a01 |
12 | 7193880180bb |
13 | 2c6a98b28357 |
14 | 1450a9692931 |
15 | 93241d87325 |
hex | 4d49122078f |
5311014504335 has 4 divisors (see below), whose sum is σ = 6373217405208. Its totient is φ = 4248811603464.
The previous prime is 5311014504319. The next prime is 5311014504347. The reversal of 5311014504335 is 5334054101135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5311014504335 - 24 = 5311014504319 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5311014504295 and 5311014504304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 531101450429 + ... + 531101450438.
It is an arithmetic number, because the mean of its divisors is an integer number (1593304351302).
Almost surely, 25311014504335 is an apocalyptic number.
5311014504335 is a deficient number, since it is larger than the sum of its proper divisors (1062202900873).
5311014504335 is a wasteful number, since it uses less digits than its factorization.
5311014504335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1062202900872.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 5311014504335 in words is "five trillion, three hundred eleven billion, fourteen million, five hundred four thousand, three hundred thirty-five".
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