Base | Representation |
---|---|
bin | 11000001001101110111101… |
… | …11101010010101111011101 |
3 | 20222001100210200122001020211 |
4 | 30010313132331102233131 |
5 | 23430132322333141131 |
6 | 304542510044412421 |
7 | 14121100240466164 |
oct | 1404673675225735 |
9 | 228040720561224 |
10 | 53111011224541 |
11 | 15a17287264936 |
12 | 5b5932a247111 |
13 | 23834680b9c9a |
14 | d1882db143db |
15 | 6218151485b1 |
hex | 304ddef52bdd |
53111011224541 has 16 divisors (see below), whose sum is σ = 58350795027840. Its totient is φ = 48116705978880.
The previous prime is 53111011224529. The next prime is 53111011224589. The reversal of 53111011224541 is 14542211011135.
It is a cyclic number.
It is not a de Polignac number, because 53111011224541 - 237 = 52973572271069 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53111011254541) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12475320 + ... + 16181953.
It is an arithmetic number, because the mean of its divisors is an integer number (3646924689240).
Almost surely, 253111011224541 is an apocalyptic number.
It is an amenable number.
53111011224541 is a deficient number, since it is larger than the sum of its proper divisors (5239783803299).
53111011224541 is a wasteful number, since it uses less digits than its factorization.
53111011224541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28661556.
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 53111011224541 its reverse (14542211011135), we get a palindrome (67653222235676).
The spelling of 53111011224541 in words is "fifty-three trillion, one hundred eleven billion, eleven million, two hundred twenty-four thousand, five hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •