Base | Representation |
---|---|
bin | 100110101001001100110… |
… | …0001011010001111001001 |
3 | 200210202000112121120112012 |
4 | 1031102121201122033021 |
5 | 1144004221221000441 |
6 | 15143524441225305 |
7 | 1055501243514560 |
oct | 115223141321711 |
9 | 20722015546465 |
10 | 5311155250121 |
11 | 17684a274a336 |
12 | 719407192235 |
13 | 2c6abc036c96 |
14 | 1450c024cbd7 |
15 | 9324e3d99eb |
hex | 4d49985a3c9 |
5311155250121 has 8 divisors (see below), whose sum is σ = 6070269770304. Its totient is φ = 4552135243920.
The previous prime is 5311155250067. The next prime is 5311155250151. The reversal of 5311155250121 is 1210525511135.
5311155250121 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5311155250121 - 222 = 5311151055817 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5311155250151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23508035 + ... + 23732888.
It is an arithmetic number, because the mean of its divisors is an integer number (758783721288).
Almost surely, 25311155250121 is an apocalyptic number.
It is an amenable number.
5311155250121 is a deficient number, since it is larger than the sum of its proper divisors (759114520183).
5311155250121 is a wasteful number, since it uses less digits than its factorization.
5311155250121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47256991.
The product of its (nonzero) digits is 7500, while the sum is 32.
The spelling of 5311155250121 in words is "five trillion, three hundred eleven billion, one hundred fifty-five million, two hundred fifty thousand, one hundred twenty-one".
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