Base | Representation |
---|---|
bin | 100110101001001100110… |
… | …0001011010001111010111 |
3 | 200210202000112121120112201 |
4 | 1031102121201122033113 |
5 | 1144004221221001020 |
6 | 15143524441225331 |
7 | 1055501243514610 |
oct | 115223141321727 |
9 | 20722015546481 |
10 | 5311155250135 |
11 | 17684a274a349 |
12 | 719407192247 |
13 | 2c6abc036ca7 |
14 | 1450c024cc07 |
15 | 9324e3d9a0a |
hex | 4d49985a3d7 |
5311155250135 has 16 divisors (see below), whose sum is σ = 7348329089856. Its totient is φ = 3609705512448.
The previous prime is 5311155250067. The next prime is 5311155250151. The reversal of 5311155250135 is 5310525511135.
5311155250135 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5311155250135 - 29 = 5311155249623 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5311155250094 and 5311155250103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 671444244 + ... + 671452153.
It is an arithmetic number, because the mean of its divisors is an integer number (459270568116).
Almost surely, 25311155250135 is an apocalyptic number.
5311155250135 is a deficient number, since it is larger than the sum of its proper divisors (2037173839721).
5311155250135 is a wasteful number, since it uses less digits than its factorization.
5311155250135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1342896522.
The product of its (nonzero) digits is 56250, while the sum is 37.
The spelling of 5311155250135 in words is "five trillion, three hundred eleven billion, one hundred fifty-five million, two hundred fifty thousand, one hundred thirty-five".
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