5311310131135 has 4 divisors (see below), whose sum is σ = 6373572157368. Its totient is φ = 4249048104904.

The previous prime is 5311310131111. The next prime is 5311310131151.

5311310131135 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5311310131135 - 2⁵ = 5311310131103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 531131013109 + ... + 531131013118.

It is an arithmetic number, because the mean of its divisors is an integer number (1593393039342).

Almost surely, 2^{5311310131135} is an apocalyptic number.

5311310131135 is a deficient number, since it is larger than the sum of its proper divisors (1062262026233).

5311310131135 is a wasteful number, since it uses less digits than its factorization.

5311310131135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1062262026232.

The product of its (nonzero) digits is 2025, while the sum is 28.

It can be divided in two parts, 5311310 and 131135, that added together give a palindrome (5442445).

The spelling of 5311310131135 in words is "five trillion, three hundred eleven billion, three hundred ten million, one hundred thirty-one thousand, one hundred thirty-five".