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5311355140111 = 9343568484977
BaseRepresentation
bin100110101001010010101…
…1011111011100000001111
3200210202112110202001001011
41031102211123323200033
51144010123403440421
615144000341430051
71055506221533326
oct115224533734017
920722473661034
105311355140111
111768595567679
1271946210b327
132c6b21583197
141450dca030bd
1593261c214e1
hex4d4a56fb80f

5311355140111 has 4 divisors (see below), whose sum is σ = 5311923634432. Its totient is φ = 5310786645792.

The previous prime is 5311355140109. The next prime is 5311355140121. The reversal of 5311355140111 is 1110415531135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5311355140111 - 21 = 5311355140109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5311355140121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 284233146 + ... + 284251831.

It is an arithmetic number, because the mean of its divisors is an integer number (1327980908608).

Almost surely, 25311355140111 is an apocalyptic number.

5311355140111 is a deficient number, since it is larger than the sum of its proper divisors (568494321).

5311355140111 is an equidigital number, since it uses as much as digits as its factorization.

5311355140111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 568494320.

The product of its (nonzero) digits is 4500, while the sum is 31.

The spelling of 5311355140111 in words is "five trillion, three hundred eleven billion, three hundred fifty-five million, one hundred forty thousand, one hundred eleven".

Divisors: 1 9343 568484977 5311355140111