Base | Representation |
---|---|
bin | 1001111001001010… |
… | …11111110110010011 |
3 | 111201011101121020221 |
4 | 10330211133312103 |
5 | 41334211230120 |
6 | 2235014213511 |
7 | 245423260522 |
oct | 47445376623 |
9 | 14634347227 |
10 | 5311430035 |
11 | 2286188aaa |
12 | 1042954297 |
13 | 66852c112 |
14 | 3855ac4b9 |
15 | 2114720aa |
hex | 13c95fd93 |
5311430035 has 8 divisors (see below), whose sum is σ = 6374236176. Its totient is φ = 4248797280.
The previous prime is 5311430027. The next prime is 5311430041. The reversal of 5311430035 is 5300341135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5311430035 - 23 = 5311430027 is a prime.
It is a super-2 number, since 2×53114300352 = 56422578033400202450, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5311429991 and 5311430009.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37897 + ... + 109813.
It is an arithmetic number, because the mean of its divisors is an integer number (796779522).
Almost surely, 25311430035 is an apocalyptic number.
5311430035 is a deficient number, since it is larger than the sum of its proper divisors (1062806141).
5311430035 is a wasteful number, since it uses less digits than its factorization.
5311430035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86693.
The product of its (nonzero) digits is 2700, while the sum is 25.
The square root of 5311430035 is about 72879.5584166095. The cubic root of 5311430035 is about 1744.7658610383.
Subtracting from 5311430035 its reverse (5300341135), we obtain a square (11088900 = 33302).
The spelling of 5311430035 in words is "five billion, three hundred eleven million, four hundred thirty thousand, thirty-five".
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