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53123606886533 = 173124918052149
BaseRepresentation
bin11000001010000110011011…
…01101111011100010000101
320222002120022111120222020112
430011003031231323202011
523430334121330332113
6304552351553242405
714122024334033621
oct1405031555734205
9228076274528215
1053123606886533
1115a21660181147
125b5b864563405
1323846c478ba11
14d192a68aa181
15621d00d2b5a8
hex3050cdb7b885

53123606886533 has 4 divisors (see below), whose sum is σ = 56248524938700. Its totient is φ = 49998688834368.

The previous prime is 53123606886503. The next prime is 53123606886583. The reversal of 53123606886533 is 33568860632135.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 44037584310724 + 9086022575809 = 6636082^2 + 3014303^2 .

It is a cyclic number.

It is not a de Polignac number, because 53123606886533 - 226 = 53123539777669 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53123606886503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1562459026058 + ... + 1562459026091.

It is an arithmetic number, because the mean of its divisors is an integer number (14062131234675).

Almost surely, 253123606886533 is an apocalyptic number.

It is an amenable number.

53123606886533 is a deficient number, since it is larger than the sum of its proper divisors (3124918052167).

53123606886533 is a wasteful number, since it uses less digits than its factorization.

53123606886533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3124918052166.

The product of its (nonzero) digits is 55987200, while the sum is 59.

The spelling of 53123606886533 in words is "fifty-three trillion, one hundred twenty-three billion, six hundred six million, eight hundred eighty-six thousand, five hundred thirty-three".

Divisors: 1 17 3124918052149 53123606886533