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531243103151 = 1761350978131
BaseRepresentation
bin1111011101100001000…
…11100111001110101111
31212210020020121210120002
413232300203213032233
532200441213300101
61044014423214515
753244461604545
oct7566043471657
91783206553502
10531243103151
11195331978302
1286b602a743b
133b132c19467
141b9d87bbd95
15dc4395dd6b
hex7bb08e73af

531243103151 has 8 divisors (see below), whose sum is σ = 563410314864. Its totient is φ = 499177848960.

The previous prime is 531243103141. The next prime is 531243103169. The reversal of 531243103151 is 151301342135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 531243103151 - 210 = 531243102127 is a prime.

It is a super-3 number, since 3×5312431031513 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (531243103141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25478645 + ... + 25499486.

It is an arithmetic number, because the mean of its divisors is an integer number (70426289358).

Almost surely, 2531243103151 is an apocalyptic number.

531243103151 is a deficient number, since it is larger than the sum of its proper divisors (32167211713).

531243103151 is a wasteful number, since it uses less digits than its factorization.

531243103151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50978761.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 531243103151 its reverse (151301342135), we get a palindrome (682544445286).

The spelling of 531243103151 in words is "five hundred thirty-one billion, two hundred forty-three million, one hundred three thousand, one hundred fifty-one".

Divisors: 1 17 613 10421 50978131 866628227 31249594303 531243103151