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53124431053 = 192796022687
BaseRepresentation
bin110001011110011101…
…100111110011001101
312002010022222201021111
4301132131213303031
51332244323243203
640223252532021
73560321133121
oct613635476315
9162108881244
1053124431053
11205913a1381
12a367321011
13501816ccb5
1427dd687581
1515add1726d
hexc5e767ccd

53124431053 has 4 divisors (see below), whose sum is σ = 55920453760. Its totient is φ = 50328408348.

The previous prime is 53124431051. The next prime is 53124431069. The reversal of 53124431053 is 35013442135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53124431053 - 21 = 53124431051 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53124431051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1398011325 + ... + 1398011362.

It is an arithmetic number, because the mean of its divisors is an integer number (13980113440).

Almost surely, 253124431053 is an apocalyptic number.

It is an amenable number.

53124431053 is a deficient number, since it is larger than the sum of its proper divisors (2796022707).

53124431053 is a wasteful number, since it uses less digits than its factorization.

53124431053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2796022706.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 53124431053 its reverse (35013442135), we get a palindrome (88137873188).

The spelling of 53124431053 in words is "fifty-three billion, one hundred twenty-four million, four hundred thirty-one thousand, fifty-three".

Divisors: 1 19 2796022687 53124431053